### Home > APCALC > Chapter 10 > Lesson 10.1.4 > Problem10-50

10-50.

Jules wants to hang a garland in the shape of $f(x) = 2(x^2 + 1)^{–2}$ for $-2 ≤ x ≤ 2$ where $x$ is measured in feet. How long does his garland need to be? Homework Help ✎

The general formula for arc length is:

$\int_{a}^{b}\sqrt{1+(f'(x))^2}dx$

$\int_{-2}^{2}\sqrt{1+(-4(x^2+1)^{-3}(2x))^2}dx$

Use a calculator to complete the integration.