### Home > APCALC > Chapter 10 > Lesson 10.1.8 > Problem10-96

10-96.

Examine the following series. Use one of the tests you have learned so far to determine if the series converges or diverges. State the tests you used.

1. $\displaystyle\sum _ { n = 1 } ^ { \infty } ( \frac { 1 } { 2 n } - \frac { 1 } { 3 n } )$

$\frac{1}{2n}-\frac{1}{3n}=\frac{1}{6n}$

1. $\displaystyle\sum _ { n = 1 } ^ { \infty } \frac { n ! } { ( 2 n ) ! }$

$\lim\limits_{n\to\infty}\frac{(n+1)!/(2n+2)!}{n!/(2n)!}$

$=\lim\limits_{n\to\infty}\Bigg(\frac{(n+1)!}{n!}\cdot\frac{(2n)!}{(2n+2)!}\Bigg)$

$=\lim\limits_{n\to\infty}\frac{n+1}{(2n+2)(2n+1)}=?$

1. $\displaystyle\sum _ { n = 1 } ^ { \infty } n e ^ { - n ^ { 2 } }$

$ne^{-n^2}=\frac{n}{e^{n^2}}$

$\lim\limits_{n\to\infty}\frac{(n+1)/e^{(n+1)^2}}{n/e^{n^2}}$