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7-52.

Let $f^\prime(x) =\frac { \operatorname { ln } | x - 2 | } { 3 }$ and $f(−3) =\frac { 7 } { 3 }$.

1. Estimate $f(−3.1)$

Do NOT find an $f(x)$ function. That would be tedious and unnecessary work.

This is another way of wording a very familiar problem:
'Given $f^\prime(x)$ and a point on $f(x)$, find the tangent line to $f(x)$ at $x = −3$ and use it to estimate the value of $f(−3.1)$.'

2. Find $f^{\prime\prime}(x)$

Split the absolute value into a piecewise function and differentiate.
Or, you could recall a special note about the antiderivative of $x^{−1}$: While you can generally leave it as $\ln(x)$, it actually equals $\ln\left|x\right|$.

3. Use concavity to determine if your answer to part (a) is an underestimate or an overestimate of the actual value of $f(–3.1)$. Justify your answer.

If a function is concave down, all tangent lines will be above the curve.
If a function is concave up, all tangent lines will be below the curve. Sketch this to verify.