### Home > APCALC > Chapter 9 > Lesson 9.2.1 > Problem9-49

9-49.

Without a calculator, determine the absolute minimum of $y = x^{2/3}$ over the interval $−3 ≤ x ≤ 3$. Justify your answer. Then check your solution on your graphing calculator.

$x^{2/3} = (x^2)^{1/3}$, to the $y$-values of this function are always ...

Graph the function on a calculator.