### Home > CALC > Chapter 1 > Lesson 1.4.2 > Problem1-154

1-154.

$\text{If sin is }\frac{\text{opposite}}{\text{hypotenuse}}\text{ then you know that the hypotenuse is a multiple of 2 and the}$

opposite side is half that. What kind of special right triangle fulfills those conditions?

$\frac{\sqrt{3}}{2}$

$\text{tan}(x)=\frac{\text{sin}(x)}{\text{cos}(x)}$

$\text{sec}(x)=\frac{1}{\text{cos}(x)}$

$\text{csc}(x)=\frac{1}{\text{sin}(x)}$