### Home > CALC > Chapter 1 > Lesson 1.4.2 > Problem1-154

1-154.

If $\operatorname { sin } x = \frac { 1 } { 2 }$ and if $0 \leq x \leq \frac { \pi } { 2 }$, then without a calculator evaluate:

1. $\text{cos}(x)$

If sin is $\frac{\text{opposite}}{\text{hypotenuse}}$ then you know that the hypotenuse is a multiple of $2$ and the opposite side is half that. What kind of special right triangle fulfills those conditions?

$\frac{\sqrt{3}}{2}$

1. $\text{tan}(x)$

$\text{tan}(x)=\frac{\text{sin}(x)}{\text{cos}(x)}$

1. $\text{sec}(x)$

$\text{sec}(x)=\frac{1}{\text{cos}(x)}$

1. $\text{csc}(x)$

$\text{csc}(x)=\frac{1}{\text{sin}(x)}$