Home > CALC > Chapter 1 > Lesson 1.4.4 > Problem1-189

1-189.

Let $g(x) = (3x - 1)^2$.

1. Find $g(-5)$.

$g(−5) = 256$

2. Find $g(a + 1)$ and simplify.

Substitute $(a + 1)$ for $x$. Simplify.

3. If $g(x) = 49$, find $x$.

Set $(3x - 1)^²$ equal to $49$ and solve for $x$.

4. Find $g^{−1} (x)$.

Let $g(x) = y$. Solve for $x$. Then switch the $x$ and $y$.

Remember the $±$.