### Home > CALC > Chapter 10 > Lesson 10.4.1 > Problem10-139

10-139.

$v_{\text{avg}}=\frac{1}{18-0}\int_0^{18}v(t)dt$

Use a calculator to evaluate this integral.

In this case, average velocity is total distance divided by total time.

$v_{\text{avg}}=\frac{s(18)-s(0)}{18-0}$