CPM Homework Help : CALC Problem 11-10

If vector $\vec { a } = \langle - 2,5 )$ , $\vec { b } = \langle 6,0 \rangle$ , and $\vec { c } = \langle \frac { 3 } { 2 } , 8 )$ , find:

$2 \vec { c } - \vec { a }$
Step 1(a):
$2\big<\frac{3}{2},8\big>-\big<-2,5\big>$
Step 2(a):
$\big<3,16\big>-\big<-2,5\big>$

$|| \vec { a } + \vec { b } ||$
Hint (c):
Express $\vec{a}+\vec{b}$ as a single vector.
More Help (c):
The double bars indicate "the length of". Use the Pythagorean Theorem to calculate this length.