Home > CALC > Chapter 12 > Lesson 12.1.3 > Problem12-39

12-39.

$\vec{v}(t)=\langle v_0\cos(\theta),v_0\sin(\theta)+a(t)\rangle=\langle 40\cos\Big(\frac{\pi}{6}\Big),40\sin\Big(\frac{\pi}{6}\Big)-10t\rangle$

$x(t)=40t\cos\Big(\frac{\pi}{6}\Big)+C_1\text{ }y(t)=40t\sin\Big(\frac{\pi}{6}\Big)-5t^2+C_2$

First, determine when the ball hits the ground. This is when y(t) = 0.

Then angle is the angle created by the slope.
Think of drawing a slope triangle and calculating the angle.