Let $u = x + 1$.
Once you rewrite the integrand, you should recognize it as a special case.

Let $u =\operatorname{sin}(x)$.

$\operatorname{sin}(2x) = 2\operatorname{sin}(x)\operatorname{cos}(x)$

Let $u =\operatorname{sin}^2(x) + 1$.

$\operatorname{ln}(x^2) = 2\operatorname{ln}(x)$