Evaluate.

Before finding the limit, factor the numerator and the denominator. If the '$0$' in the denominator cancels out, then the limit exists.

For all limits as $x →∞$, you are looking for end behavior. For example, is there a horizontal asymptote? Or does the function approach $+∞$ or $−∞$ in the end? To answer this question, compare the highest power in the numerator with the highest power in the denominator.

Highest power in the numerator: $x^2$
Highest power in the denominator: $x^2$
$\lim\limits_{x\rightarrow \infty }\frac{x^{2}}{x^{^{2}}}=\lim\limits_{x\rightarrow \infty }1=1$
Note: this means that $f(x)$ has a horizontal asymptote of $y = 1$.

First, factor the expression. Visualize the left-hand and right-hand limits of the simplified function. Do they match up?

You can prove this by showing that $\lim\limits_{x\rightarrow 0^{-1}}f(x)\neq \lim\limits_{x\rightarrow 0^{+}}f(x).$
Limit does not exist.