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Home > CALC > Chapter 4 > Lesson 4.3.2 > Problem 4-109

4-109.

To set up the integral, first determine the bounds in which this function exists in the 2nd quadrant.

Determine the roots:
0 = x3 + 2x2 − 3x
0 = x(x2 + 2x − 3) = x(x + 3)(x − 1)
Roots: x = 0, x = −3, and x = 1
2nd quadrant domain: [−3, 0]

Integrate.