As a log falls in a waterfall, its velocity is v(t) = −32t − 18 in feet per second. The position of the log at time t = 0 was at the top of the waterfall, 500 feet above sea level. Homework Help ✎
Where is the log after 1 second? 2 seconds? 3 seconds?
Where is the log after t seconds? This is the position function s(t). What is its relationship to v(t) ?
You need to find the position function, s(t).
Solve for C, by evaluating the given point s(0)=500.
Check your work:
s(1) = 466 ft
s(2) = 400 ft
s(3) = 302 ft
Refer to the hint in part (a).
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