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5-9.

The Math Booster Club shot a rocket from the ground straight up into the air to celebrate π Day. The launcher shot the rocket with a starting velocity of 182 ft/sec. Find a function s(t) for the height of the rocket. Then find its maximum height and the amount of time it was in the air. Homework Help ✎

Start with the basic equation: s(t) = −16t² + v0t + s0 where v0 is the initial velocity and s0 is the initial height of the rocket from the ground.

The initial height of the rocket is 0 because it is shot from the ground.

The initial velocity is 182 ft/sec. Thus: s(t) = −16t2 + 182t

To find the maximum height, take the derivative of the function and set it equal to zero because the maximum height occurs when the velocity is zero.

0 = −32t +182