### Home > CALC > Chapter 6 > Lesson 6.1.1 > Problem 6-9

6-9.

Find the inverse,

*f*^{−1}(*x*), for the following functions. Homework Help ✎*f*(*x*)*=*2^{x}*f*(*x*) = log_{3}*x**f*(*x*)*=*1og_{e}x*f*(*x*)*=*5 · 9^{ }^{x}

Solve for *x*: log_{2}*y* = *x*

Then 'switch' the input and the output.

*f*^{ −1}(*x*) = log_{2}*x*

This is the reverse of part (a).

Recall that e is a constant. (It's value is between 2 and 3)

*f*^{ −1}(*x*) = e^{x}

Be sure to divide both sides by 5 before you solve for *x* .