### Home > CALC > Chapter 9 > Lesson 9.2.1 > Problem9-57

9-57.

No calculator! A particle's position as function of time is defined as $x = 2t$ and $y = \sqrt { t + 3 } + 1$. Create a table for $-3 ≤ t ≤ 3$ and carefully graph the equation on graph paper.

Complete the table. Then be sure to graph the $(x, y)$ points.
$\left. \begin{array} { | c | c | c | } \hline t & { x = 2 t } & { y = \sqrt { t + 3 } + 1 } \\ \hline - 3 & { - 6 } & { 1 } \\ \hline - 2 & { - 4 } & { 2 } \\ \hline - 1 & { } \\ \hline 0 \\ \hline 1 \\ { 1 } \\ { 2 } \\ { 3 } \\ \hline \end{array} \right.$