Solve the systems of equations below. Homework Help ✎
y = 3x
2y – 5x = 4
x – 4 = y
–12 = 3y – 3x
Read the Math Notes box in Lesson 6.2.3 to review the Substitution Method. Use it to solve both parts.
To start part (a) substitute 3x in for y into the second equation 2y − 5x = 4. So 2(3x) − 5x = 4.
Solve for x.
Once you solve for x, substitute that value in for x into one of the original equations: y = 3x or 2y − 5x = 4.
Solve for y.
Put the answer in point form (x, y).
The final answer is (4,12).
Substitute (x − 4) in for y in the second equation
-12 = 3(x-4) − 3x.
Follow steps 2 and 3 from part (a).
Read the Math Notes box in Lesson 6.4.1 to review the different types of solutions for systems of equations.