### Home > CC4 > Chapter 7 > Lesson 7.1.1 > Problem 7-11

7-11.

Solve the systems of equations below. Homework Help ✎

*y*= 3*x*

2*y*– 5*x*= 4*x*– 4 =*y*

–12 = 3*y*– 3*x*

Read the Math Notes box in Lesson 6.2.3 to review the Substitution Method. Use it to solve both parts.

To start part (a) substitute 3*x* in for *y* into the second equation 2*y* − 5*x* = 4. So 2(3*x*) − 5*x* = 4.

Solve for *x*.

Once you solve for *x*, substitute that value in for *x* into one of the original equations: *y* = 3*x* or 2*y* − 5*x* = 4.

Solve for *y*.

Put the answer in point form (*x*, *y*).

The final answer is (4,12).

Substitute (*x* − 4) in for *y* in the second equation

-12 = 3(*x*-4) − 3*x*.

Follow steps 2 and 3 from part (a).

Read the Math Notes box in Lesson 6.4.1 to review the different types of solutions for systems of equations.