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Home > CC4 > Chapter 8 > Lesson 8.2.3 > Problem 8-120

8-120.

BE is the midsegment of ΔACD, shown below. What is the perimeter of ΔACD? Homework Help ✎

The perimeter of ΔACD = (2)(the perimeter of ΔABE) because the midsegment cuts the sides in half.