Since $8 = 2^3, (2^3)^x = 2^6$

$2^{(3x)} = 2^6$

$3x = 6$

$x = 2$

$(3^2)^2 = 3^{2x+1}$

$x = 1.5$

Use the same method as part (a).

$\text{Remember that }\frac{1}{2}=2^{-1}.$