CPM Homework Help : INT1 Problem 7-27

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Home > INT1 > Chapter 7 > Lesson 7.1.2 > Problem 7-27

7-27.

Solve each system.

Hint :

Read Math Notes box in Lesson 6.2.3 on the substitution method.

$6x − 2y = 10$
$3x − 2 = y$
Answer (a):
There is no solution.

$3x − 9y = 3$
$2x = 16 − y$
Step 1(b):
Solve the lower equation for $y$ , and then substitute the expression for $y$ into the top equation and solve.

$y = 3x + 1$
$x + 2y = −5$
Step 1 (c):
Substitute $3x + 1$ for y in the second equation.
Answer (c):
$(−1, −2)$

$2x + 3y = 9$
$x − 2y = 1$
Step 1(d):
Multiply the entire second equation by $−2$
Step 2(d):
Add the equations together.
Answer (d):
$(3, 1)$

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