### Home > INT1 > Chapter 9 > Lesson 9.3.3 > Problem9-93

9-93.

Solve each equation.

1. $3(x-2)=-6$

Distribute the $3$ over the parentheses.
$3(x)−3(2) = −6$
$3x −6 = −6$

Add $6$ to both sides.
$3x −6 + 6 = −6 + 6$
$3x = 0$
Divide both sides by $3$.
$3x ÷ 3 = 0 ÷ 3$

$x = 0$

1. $(x+2)(x+3)=(x+1)(x+5)$

Start by using generic rectangles to rewrite both sides without parentheses. Then solve using the same method as (a).

Isolate the $x$. What happens to the $x^2$?

$x = 1$

1. $|2x-5|=17$

Remember there are $2$ solutions.

Set the expression $2x − 5 = 17$ and $2x − 5 = − 1$$2x−5=−17$ because $|\text{__}|=17$ could be $17$ or $−17$.

1. $\frac { 2 x } { 9 } = \frac { 14 } { 5 }$

What is the common multiple between $9$ and $5$? It is $45$ so multiply both sides of the equation by $45$ (multiplication property of equality)