### Home > INT2 > Chapter 1 > Lesson 1.1.1 > Problem1-7

1-7.

Solve each equation, then check your solutions.

1. $\frac { x } { 8 } = \frac { 3 } { 4 }$

Multiply both sides by $8$.

$8\cdot\frac{\textit{x}}{8}=\frac{3}{4}\cdot8$

$\ \ \ \ \ \ x=\frac{24}{4}$

$x=6$

1. $\frac{2}{5}=\frac{x}{40}$

What can you multiply both sides of the equation by to eliminate the denominators?

1. $\frac { 1 } { 8 } = \frac { x } { 12 }$

$x=1.5$

1. $\frac { x } { 10 } = \frac { 12 } { 15 }$

Use the method from part (a).