### Home > INT2 > Chapter 11 > Lesson 11.1.1 > Problem11-9

11-9.

In the circle below, $CD$ is a diameter. If $AE = 10$, $CE = 4$, and $AB = 16$, what is the length of the radius of the circle?

$\frac{AE}{CE} = \frac{DE}{BE},\;\text{so}\; \frac{10}{4}=\frac{DE}{6}$

$DE = 15$

$9.5$