CPM Homework Help : INT2 Problem 11-53

A rectangular pyramid, with dashed line segments from the top vertex, perpendicular to the center of the rectangle, and from the center of rectangle, to bottom mid-point of right side triangle, and from the top vertex, perpendicular to the bottom edge of the right side triangle. This creates an internal right triangle. What are the volume and surface area of a square-based right pyramid if the base edge has length $6$ units and the height of the pyramid is $4$ units?

Hint 1:

$V=\frac{1}{3}(\text{base area})(\text{height})$

SA = total area of the $4$ faces and the base

Hint 2:

Use the Pythagorean Theorem to find the height of the triangular faces.

Partial Answer:

$SA = 96\text{ u}^2$