CPM Homework Help : INT2 Problem 11-86

Rewrite $y = x^2 + 8x + 10$ in graphing form and sketch a graph of the function. Then name the vertex and the $y$ -intercept.

Hint:

Complete the square:
$y + 16 = (x + 4)^2 + 10$
$y = (x + 4)^2 - 6$

More Help:

The vertex is the lowest point on the graph and the $y$ intercept is the point where $x = 0$ .

Answer:

Vertex $= (-4, -6)$
$y$ intercept $= (0, 10)$

Upward parabola, vertex at the point (negative 4, comma negative 6).