Assume that two six-sided dice are being rolled. Let event $A=\text{{the sum is a multiple of 3}}$ and event $B = \text{{the sum is a multiple of 4}}$.

1. How many outcomes are in the intersection of events $A$ and $B$?

   Hint (a):

   Make a table or grid with all the sum possibilities for two rolled die,
   i.e. $1+1=2$, $1+2=3$, etc.
   How many outcomes are multiples of both $3$ and $4$?

2. What is $P(A \text{ or }B)$?

   Hint (b):

   Use the table or list you made in part (a).

   More Help (b):

   Remember to exclude all outcomes that apply to both events.
   $P(A \text{ or } B) = P(A) + P(B) − P(A \text{ and } B)$

   Answer (b):

   $P\,(A\text{ or }B) = \frac{20}{36}$