CPM Homework Help : INT2 Problem 5-68

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5-68.

Rewrite the following expressions in simplified radical form.

$\sqrt { 3 } \cdot \sqrt { 6 }$
Steps (a):
$\sqrt{3\cdot 6}=\sqrt{3\cdot 3\cdot 2}$
Answer (a):
$3\sqrt{2}$

$2\sqrt { 27 } \cdot 5\sqrt { 3 }$
Step (b):
$(5\cdot2)\sqrt{27\cdot3}$

$\sqrt { 5 \cdot 16 }$
Answer (c):
$4\sqrt{5}$

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