### Home > INT2 > Chapter 5 > Lesson 5.2.5 > Problem5-112

5-112.

Solve the quadratic equation below twice: once using the Quadratic Formula and once by completing the square. You should get the same result using both methods. What happens?

$x^2 + 6x + 11 = 0$

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$a = 1, b = 6, c = 11$

No solution, you cannot take a square root of a negative. You should get no solution for completing the square, as well.