Think of this as $(xx)(xxyyy)$.

$(x^2 · x^2)(y^3) = x^4y^3$

Think of the numerator as $xxxyyyy$. Write out the denominator in the same way. Then factor out all of the $1\text{s}$.

$xy$

$(2 · −3)(x^2 · x^4)$

Write $2x$ three times and follow the pattern from part (a).