Since $8 = 2^3$, $(2^3)^x = 2^6$

$2^{(3x)}= 2^6$ 

$3x = 6$ 

$x = 2$ 

$(3^2)^2 = 3^{2x+1}$ 

$x = 1.5$ 

Use the same steps as part (a).

Remember that $\frac{1}{2}=2^{-1}.$