### Home > INT2 > Chapter 6 > Lesson 6.1.2 > Problem6-20

6-20.

Solve each equation by first rewriting the expressions in each part with the same base.

1. $8^x = 2^6$

Since $8 = 2^3$$(2^3)^x = 2^6$

$2^{(3x)}= 2^6$

$3x = 6$

$x = 2$

1. $9^2 = 3^{2x+1}$

$(3^2)^2 = 3^{2x+1}$

$x = 1.5$

1. $4^{2x} = ( \frac { 1 } { 2 } ) ^ { x + 5 }$

Use the same steps as part (a).

Remember that $\frac{1}{2}=2^{-1}.$