Use the equal values method.

Solve the quadratic equation.

Solve for $x$.

Use the $x$-values and substitute to find the $y$-values.

Write your two answer in the form $(x, y)$.

$x^2 + 2.6x + .45 = 2x + 1$

$x^2 + 0.6s - 0.55 = 0$

$(x + 1.1)(x - 0.5) = 0$