CPM Homework Help : INT3 Problem 1-72

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1-72.

Rewrite each equation by solving for $x$ . (Note that $y$ will be in your answer).

$y = \frac {3}{5}x + 1$
Hint (a):
To solve for $x$ , you need to isolate the $x$ -term. There are two ways to start. You can isolate the $x$ -term or eliminate the denominator.
Solution 1 (a):
To isolate the $x$ -term:
$y-1=\frac{3}{5}x$
$\frac{5}{3}\cdot \left(y-1\right)=\frac{3}{5}x\cdot \frac{5}{3}$
$x=\frac{5(y-1)}{3}$
Solution 2 (a):
To eliminate the denominator first:
$5\cdot y=\left(\frac{3}{5}x+1\right)\cdot 5$
$5y=3x+5$
$3x=5y-5$
$x=\frac{5y-5}{3}$

$3x + 2y = 6$
Hint (b):
See part (a).

$y = x^2$
Hint (c):
Refer to part (c) of problem 1-37.

$y = x^2 - 100$
Hint (d):
Refer to part (d) of problem 1-37.
Answer (d):
This cannot be simplified. Why?
$x=\pm\sqrt{y+100}$

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