CPM Homework Help : INT3 Problem 12-88

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Home > INT3 > Chapter 12 > Lesson 12.2.1 > Problem 12-88

12-88.

Solve the equations below.

$\frac { 3 x } { x + 2 } + \frac { 7 } { x - 2 } = 3$
Hint (a):
Multiply both sides by $\left(x + 2\right)\left(x − 2\right).$
Step (a):
$3x\left(x − 2\right) + 7\left(x + 2\right) = 3\left(x + 2\right)\left(x − 2\right)$
$3x^2−6x+7x+14=3\left(x^2−4\right)$
$3x^{2} + x + 14 = 3x^{2} − 12$
Answer (a):
$x = −26$

$( x + 2 ) ^ { 2 } + ( x - 2 ) ^ { 2 } = ( 2 x ) ^ { 2 }$
Answer (b):
$x = 10, x = 3$

$3 x ^ { 3 } + 12 x = 21 x ^ { 2 } + 84$

$10 \operatorname { ln } ( 4 ) + \operatorname { ln } ( x ) = 16$

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