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2-83.

Graph $y=x^2+6x$ without making a table. Where are the intercepts and vertex? Homework Help ✎

Set $x=0$ to find the $y$-intercepts and set $y=0$ to find the $x$-intercepts.

Average the $x$-intercepts or complete the square to find the coordinates of the vertex.

$y$-intercept: $(0,0)$; $x$-intercepts: $(0,0)$ and $(−6,0)$