### Home > INT3 > Chapter 3 > Lesson 3.1.2 > Problem3-31

3-31.

Solve $(x-3)^2-2=x+1$ graphically. Is there more than one way to do this? Explain.

Graph $y=(x−3)^2−2$ and $y=x+1$.

Which coordinates of the points of intersection will make this equation true?
Are there any $y$-values in the original equation?

Another way to do this is to set the equation equal to $0$.

Now you can graph $y=x^2−7x+6$ and $y=0$. Which points on the graph should you be looking at now?

Use the eTool below to solve the equation graphically.
Click the link at right for the full version of the eTool: Int3 3-31 HW eTool