### Home > INT3 > Chapter 3 > Lesson 3.2.1 > Problem3-84

3-84.

David comes across an equation in science class he needs to solve. It is written in scientific notation: $(4\times10^3)x-(8\times10^3)=(16\times10^3)$.

1. David writes what he thinks is an equivalent equation, $x-2=4$. Solve both equations and verify that they have the same solution.

Divide each term by $10^3$.

Simplify.
$4x−8=16$
$4x=24$

$x=6$

2. What does David do to the equation $(4\times10^3)x-(8\times10^3)=(16\times10^3)$ to change it to $x-2=4$?