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3-97.

Complete the square to rewrite $y=x^2-5x+7$ in graphing form and state the vertex. Homework Help ✎

$y-7=x^2-5x$

$y-7\ +\ ?=x^2-5x+\ ?$

$y-7+6.25=x^2-5x+6.25$

$y-0.75=(x-2.5)^2$

$y=\left(x-2.5\right)^2+0.75$

Where is the vertex?