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3-104.

Solve the system of equations below.

$x+3y=16$
$x-2y=31$

The answer for the linear system is $(25,−3)$.

1. Now write a new system by replacing $x$ with $x^2$.

$x^2+3y=16$
$x^2−2y=31$

2. What effect will this replacement have on the solution to the system? Solve the new system.

Since $x^2$ replaced $x$ and you already know the solution for $x$, what does $x^2$ equal?

The equations represent parabolas that intersect at two points.