### Home > INT3 > Chapter 4 > Lesson 4.3.2 > Problem4-81

4-81.

1. $\sqrt { x } + 2 = x$

First isolate the radical by subtracting $2$ from both sides.
$\sqrt{x} = x - 2$

Square both sides.
$x=x^2−4x+4$

Set the equation equal to $0$.
$x^2−5x+4=0$

Factor.
$(x−4)(x−1)=0$

$x=4$ ($x=1$ is extraneous)

1. $\sqrt { x } + 2 = \sqrt { x + 6 }$

You will need to square twice.