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1-52.

Given $f\left(x\right) = 2x + 5$, $g\left(x\right) = x^{2} − 1$, and $h(x) =\sqrt { x + 2 }$, find:

1. $f(g(−2))$

Evaluate $g\left(−2\right)$ first. Then substitute that value in the f function.

1. $g\left(f\left(h\left(2\right)\right)\right)$

$g(f(h(2)))= g(\sqrt{2 + 2})$

$=g(f(2))$

$=g(2(2) + 5)$

$= g(9)$

1. $f ^{−1}\left(x\right)$

1. Switch the $x$ and $y$'s
2. Solve for $y$.

1. $f\left(g\left(h\left(x\right)\right)\right)$

Follow a similar process as shown in part (b).