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1-52.

Given $f\left(x\right) = 2x + 5$ , $g\left(x\right) = x^{2} − 1$ , and $h(x) =\sqrt { x + 2 }$ , find:

$f(g(−2))$
Hint (a):
Evaluate $g\left(−2\right)$ first. Then substitute that value in the f function.

$g\left(f\left(h\left(2\right)\right)\right)$
Answer (b):
$g(f(h(2)))= g(\sqrt{2 + 2})$
$=g(f(2))$
$=g(2(2) + 5)$
$= g(9)$

$f ^{−1}\left(x\right)$
Hint (c):
1. Switch the $x$ and $y$ 's
2. Solve for $y$ .

$f\left(g\left(h\left(x\right)\right)\right)$
Hint (d):
Follow a similar process as shown in part (b).

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