$216\degree=1$

$6^{-4}$

Convert all the bases to 5.

$\frac{3\cdot19^{97}}{8\cdot 19^{94}}=$

$\frac{3}{8} \cdot 19^{97-94}=$

$\frac{3}{8} \cdot 19^3$

Follow the same process as (c).