Given $\triangle DOG$, where $∠D = 64^\circ$, $∠O = 38^\circ$, and $DO = 8$ inches.  

1. Draw a diagram that is roughly to scale.

2. Solve the triangle completely.

   Hint (b):

   Determine the measure of the missing angle. Then use the Law of Sines.

   Step (b):

   $\frac{\sin(78^\circ)}{8}=\frac{\sin(64^\circ)}{OG}$

3. Calculate the area of $\triangle DOG$.

   Hint (c)

   $A=\frac{1}{2}ab\ \sin\left(C\right)$