CPM Homework Help : PC Problem 10-55

To slide a crate across a floor, a rope is attached and pulled with a constant force of $50$ pounds at an angle of $30^\circ$ . How much work is done if the box is dragged $10$ feet?

Hint:

$\text{work} = \left(\text{force}\right) · \left(\text{distance}\right)$

More Help:

Which component of the given vector is actually moving the box forward?

Step 1:

Determine the magnitude of the horizontal component of the given vector.

Since this is a $30^\circ-60^\circ-90^\circ$ triangle, $y = 25$ and $x = 25\sqrt{3}.$

Step 2:

$\text{work} = \left(25\sqrt{3} \text{ pounds}\right)\left(10 \text{ feet}\right)$