### Home > PC > Chapter 10 > Lesson 10.1.4 > Problem10-61

10-61.

Evaluate the following limits.

1. $\lim\limits _ { x \rightarrow 2 } \frac { 2 x ^ { 3 } - 8 x } { x ^ { 2 } + x - 6 }$

Try substituting in $x = 2$. What happens?

Completely factor both the numerator and denominator. Simplify. Substitute in $x = 2$.

$\frac{16}{5}$

1. $\lim\limits _ { x \rightarrow - \infty } \frac { 2 x ^ { 3 } - 8 x } { x ^ { 2 } + x - 6 }$

Use the dominant term idea.