Combine the $\sqrt{2}$’s with the $\sqrt{2}$s and with the $\sqrt{7}$s.

$3\sqrt{2}+7\sqrt{7}$

$\sqrt[3]{2}$  is different from $\sqrt{2}$

Rewrite each term in simple radical form so that you can identify like terms.

$\sqrt{(4)(5)}+\sqrt{(9)(5)}$

$2\sqrt{5}+3\sqrt{5}$

$3\sqrt{4}\sqrt{3}-\sqrt{16}\sqrt{2}+\sqrt{9}\sqrt{3}+2\sqrt{4}\sqrt{2}$