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4-91.

Solve for $x$: $a^2x + b^2 x + 7 = 3c$

Isolate the $x$ on the left side by subtracting $7$ from both sides.

Factor out an '$x$' on the left side.

Divide both sides by $x$'s factor solving for $x$.

$a^2x + b^2x = 3c − 7$

$x(a^2 + b^2) = 3c − 7$

$x=\frac{3c-7}{(a^2+b^2)}$