### Home > PC > Chapter 6 > Lesson 6.1.3 > Problem6-47

6-47.

Find $h\left(x\right) = f\left(x + 3\right) − 2$ where $f ( x ) = \left\{ \begin{array} { l l } { - 2 x + 3 } & { \text { for } x < 1 } \\ { \sqrt { 2 x - 1 } } & { \text { for } x \geq 1 } \end{array} \right.$.

Graph the piecewise function.

Shift the graph $3$ to the left and $2$ down.