Kiara was trying to solve the problem $\sin^{2}\left(3x − 5\right) − \sin\left(3x − 5\right) + 0.24 = 0$. She originally made the substitution $u = 3x − 5$.

1. What new equation did she get?

   Answer (a):

   $\sin^{2}u − \sin u + 0.24 = 0$

2. She decided that she needed to make another substitution using the variable $v$. What would be a good substitution to make?

   Answer (b):

   Let $v = \sin u$

3. What is Kiara’s equation now?

   Answer (c):

   $v^{2} − v + 0.24 = 0$

4. If she had done the substitution in one step, what would $v$ equal?

   Answer (d):

   $v = \sin\left(3x − 5\right)$