$1050\left(1+\frac{0.07}{4}\right)^{4\cdot5}$

$5000 \left( 1+\frac{0.082}{12} \right)^ {120}$

$1. \ \ P\text{ is the initial amount.}$

$2. \ \ 1 + \frac{r}{100n}\text{ is the multiplier.}$

$3.\ \ nt \text{ is the number of times it will be compounded.}$