Draw a diagonal. If the radius is 5, how long is the diagonal?

Use the Pythagorean Theorem to find the length L.

$(2x)^2+L^2=10^2$

$L^2=100-4x^2$

$L=\sqrt{100-4x^2}$

$L=\sqrt{4(25-x^2)}$

$L=2\sqrt{25-x^2}$

Perimeter = 2(width) + 2(length)

$\text{Perimeter}=2(2x)+2(2\sqrt{25-x^2})$

$\text{Perimeter}=4x+4\sqrt{25-x^2}$

Area = (Length)(Width)

$\text{Area}=(2x)(2\sqrt{25-x^2})$

$\text{Area}=4x\sqrt{25-x^2}$